Search a number
-
+
141132132011 = 1310856317847
BaseRepresentation
bin1000001101110000100…
…0010110111010101011
3111111021202000010220102
42003130020112322223
54303014311211021
6144500223220015
713124246220503
oct2033410267253
9444252003812
10141132132011
1154943455732
1223428a4760b
13104022b31b0
146b8bb32a03
153a1030300b
hex20dc216eab

141132132011 has 4 divisors (see below), whose sum is σ = 151988449872. Its totient is φ = 130275814152.

The previous prime is 141132131983. The next prime is 141132132061. The reversal of 141132132011 is 110231231141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141132132011 is a prime.

It is a super-3 number, since 3×1411321320113 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141132132061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5428158911 + ... + 5428158936.

It is an arithmetic number, because the mean of its divisors is an integer number (37997112468).

Almost surely, 2141132132011 is an apocalyptic number.

141132132011 is a deficient number, since it is larger than the sum of its proper divisors (10856317861).

141132132011 is a wasteful number, since it uses less digits than its factorization.

141132132011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10856317860.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 141132132011 its reverse (110231231141), we get a palindrome (251363363152).

The spelling of 141132132011 in words is "one hundred forty-one billion, one hundred thirty-two million, one hundred thirty-two thousand, eleven".

Divisors: 1 13 10856317847 141132132011