Base | Representation |
---|---|
bin | 1100110101011111110100… |
… | …0111010001111011010011 |
3 | 1211222012200011020201011011 |
4 | 3031113331013101323103 |
5 | 3322212330303031233 |
6 | 50003304314231351 |
7 | 2654434413413236 |
oct | 315277507217323 |
9 | 54865604221134 |
10 | 14113214111443 |
11 | 4551420487247 |
12 | 16bb29aa25557 |
13 | 7b4b412c0735 |
14 | 36b12447141d |
15 | 1971b52800cd |
hex | cd5fd1d1ed3 |
14113214111443 has 16 divisors (see below), whose sum is σ = 15494394545280. Its totient is φ = 12795370592256.
The previous prime is 14113214111441. The next prime is 14113214111453. The reversal of 14113214111443 is 34411141231141.
It is not a de Polignac number, because 14113214111443 - 21 = 14113214111441 is a prime.
It is a super-3 number, since 3×141132141114433 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14113214111441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32843355 + ... + 33270292.
It is an arithmetic number, because the mean of its divisors is an integer number (968399659080).
Almost surely, 214113214111443 is an apocalyptic number.
14113214111443 is a deficient number, since it is larger than the sum of its proper divisors (1381180433837).
14113214111443 is a wasteful number, since it uses less digits than its factorization.
14113214111443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66114126.
The product of its digits is 4608, while the sum is 31.
Adding to 14113214111443 its reverse (34411141231141), we get a palindrome (48524355342584).
The spelling of 14113214111443 in words is "fourteen trillion, one hundred thirteen billion, two hundred fourteen million, one hundred eleven thousand, four hundred forty-three".
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