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14113214111443 = 172943366113647
BaseRepresentation
bin1100110101011111110100…
…0111010001111011010011
31211222012200011020201011011
43031113331013101323103
53322212330303031233
650003304314231351
72654434413413236
oct315277507217323
954865604221134
1014113214111443
114551420487247
1216bb29aa25557
137b4b412c0735
1436b12447141d
151971b52800cd
hexcd5fd1d1ed3

14113214111443 has 16 divisors (see below), whose sum is σ = 15494394545280. Its totient is φ = 12795370592256.

The previous prime is 14113214111441. The next prime is 14113214111453. The reversal of 14113214111443 is 34411141231141.

It is not a de Polignac number, because 14113214111443 - 21 = 14113214111441 is a prime.

It is a super-3 number, since 3×141132141114433 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14113214111441) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32843355 + ... + 33270292.

It is an arithmetic number, because the mean of its divisors is an integer number (968399659080).

Almost surely, 214113214111443 is an apocalyptic number.

14113214111443 is a deficient number, since it is larger than the sum of its proper divisors (1381180433837).

14113214111443 is a wasteful number, since it uses less digits than its factorization.

14113214111443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66114126.

The product of its digits is 4608, while the sum is 31.

Adding to 14113214111443 its reverse (34411141231141), we get a palindrome (48524355342584).

The spelling of 14113214111443 in words is "fourteen trillion, one hundred thirteen billion, two hundred fourteen million, one hundred eleven thousand, four hundred forty-three".

Divisors: 1 17 29 433 493 7361 12557 213469 66113647 1123931999 1917295763 28627209151 32594027971 486662555567 830189065379 14113214111443