141132443244433 has 8 divisors (see below), whose sum is σ = 141966191314368. Its totient is φ = 140298901538064.

The previous prime is 141132443244421. The next prime is 141132443244487. The reversal of 141132443244433 is 334442344231141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141132443244433 is a prime.

It is a super-3 number, since 3×141132443244433³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141132443244433.

It is not an unprimeable number, because it can be changed into a prime (141132443244733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50218941 + ... + 52954762.

It is an arithmetic number, because the mean of its divisors is an integer number (17745773914296).

Almost surely, 2^{141132443244433} is an apocalyptic number.

It is an amenable number.

141132443244433 is a deficient number, since it is larger than the sum of its proper divisors (833748069935).

141132443244433 is a wasteful number, since it uses less digits than its factorization.

141132443244433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103181783.

The product of its digits is 1327104, while the sum is 43.

Adding to 141132443244433 its reverse (334442344231141), we get a palindrome (475574787475574).

The spelling of 141132443244433 in words is "one hundred forty-one trillion, one hundred thirty-two billion, four hundred forty-three million, two hundred forty-four thousand, four hundred thirty-three".