Base | Representation |
---|---|
bin | 11010010010011011… |
… | …11101111110110011 |
3 | 1100102120122221111202 |
4 | 31021031331332303 |
5 | 212401001103103 |
6 | 10252241001415 |
7 | 1006512034256 |
oct | 151115757663 |
9 | 40376587452 |
10 | 14113300403 |
11 | 5a92654534 |
12 | 289a62326b |
13 | 143bc2b537 |
14 | 97c56b09d |
15 | 579063988 |
hex | 34937dfb3 |
14113300403 has 4 divisors (see below), whose sum is σ = 14117950560. Its totient is φ = 14108650248.
The previous prime is 14113300393. The next prime is 14113300433. The reversal of 14113300403 is 30400331141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14113300403 - 28 = 14113300147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14113300433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2320523 + ... + 2326596.
It is an arithmetic number, because the mean of its divisors is an integer number (3529487640).
Almost surely, 214113300403 is an apocalyptic number.
14113300403 is a deficient number, since it is larger than the sum of its proper divisors (4650157).
14113300403 is an equidigital number, since it uses as much as digits as its factorization.
14113300403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4650156.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 14113300403 its reverse (30400331141), we get a palindrome (44513631544).
The spelling of 14113300403 in words is "fourteen billion, one hundred thirteen million, three hundred thousand, four hundred three".
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