1411333121 has 4 divisors (see below), whose sum is σ = 1539636144. Its totient is φ = 1283030100.

The previous prime is 1411333073. The next prime is 1411333123. The reversal of 1411333121 is 1213331141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1411333121 - 2¹⁸ = 1411070977 is a prime.

It is a super-2 number, since 2×1411333121² = 3983722356863201282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411333093 and 1411333102.

It is not an unprimeable number, because it can be changed into a prime (1411333123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64151495 + ... + 64151516.

It is an arithmetic number, because the mean of its divisors is an integer number (384909036).

Almost surely, 2^1411333121 is an apocalyptic number.

1411333121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1411333121 is a deficient number, since it is larger than the sum of its proper divisors (128303023).

1411333121 is a wasteful number, since it uses less digits than its factorization.

1411333121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128303022.

The product of its digits is 216, while the sum is 20.

The square root of 1411333121 is about 37567.7138111970. The cubic root of 1411333121 is about 1121.6994610564.

Adding to 1411333121 its reverse (1213331141), we get a palindrome (2624664262).

The spelling of 1411333121 in words is "one billion, four hundred eleven million, three hundred thirty-three thousand, one hundred twenty-one".