Base | Representation |
---|---|
bin | 11010010010011100… |
… | …10111100010100011 |
3 | 1100102120212021010002 |
4 | 31021032113202203 |
5 | 212401012430331 |
6 | 10252243130215 |
7 | 1006512651422 |
oct | 151116274243 |
9 | 40376767102 |
10 | 14113405091 |
11 | 5a92716155 |
12 | 289a67396b |
13 | 143bc67096 |
14 | 97c5972b9 |
15 | 5790849cb |
hex | 3493978a3 |
14113405091 has 4 divisors (see below), whose sum is σ = 14114242512. Its totient is φ = 14112567672.
The previous prime is 14113405087. The next prime is 14113405099. The reversal of 14113405091 is 19050431141.
14113405091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14113405091 - 22 = 14113405087 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14113405099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 392900 + ... + 427313.
It is an arithmetic number, because the mean of its divisors is an integer number (3528560628).
Almost surely, 214113405091 is an apocalyptic number.
14113405091 is a deficient number, since it is larger than the sum of its proper divisors (837421).
14113405091 is an equidigital number, since it uses as much as digits as its factorization.
14113405091 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 837420.
The product of its (nonzero) digits is 2160, while the sum is 29.
The spelling of 14113405091 in words is "fourteen billion, one hundred thirteen million, four hundred five thousand, ninety-one".
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