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141138433 = 347406739
BaseRepresentation
bin10000110100110…
…01101000000001
3100211120120112101
420122121220001
5242112412213
622001030401
73332441212
oct1032315001
9324516471
10141138433
117273a437
123b325401
1323318587
1414a5d409
15c5cdbdd
hex8699a01

141138433 has 4 divisors (see below), whose sum is σ = 141545520. Its totient is φ = 140731348.

The previous prime is 141138421. The next prime is 141138449. The reversal of 141138433 is 334831141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334831141 = 1073129263.

It is a cyclic number.

It is not a de Polignac number, because 141138433 - 29 = 141137921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141138493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203023 + ... + 203716.

It is an arithmetic number, because the mean of its divisors is an integer number (35386380).

Almost surely, 2141138433 is an apocalyptic number.

It is an amenable number.

141138433 is a deficient number, since it is larger than the sum of its proper divisors (407087).

141138433 is an equidigital number, since it uses as much as digits as its factorization.

141138433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 407086.

The product of its digits is 3456, while the sum is 28.

The square root of 141138433 is about 11880.1697378447. The cubic root of 141138433 is about 520.6530663071.

Adding to 141138433 its reverse (334831141), we get a palindrome (475969574).

The spelling of 141138433 in words is "one hundred forty-one million, one hundred thirty-eight thousand, four hundred thirty-three".

Divisors: 1 347 406739 141138433