14114055242433 has 4 divisors (see below), whose sum is σ = 18818740323248. Its totient is φ = 9409370161620.

The previous prime is 14114055242351. The next prime is 14114055242461. The reversal of 14114055242433 is 33424255041141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14114055242433 - 2⁹ = 14114055241921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14114055242391 and 14114055242400.

It is not an unprimeable number, because it can be changed into a prime (14114055242533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2352342540403 + ... + 2352342540408.

It is an arithmetic number, because the mean of its divisors is an integer number (4704685080812).

Almost surely, 2^{14114055242433} is an apocalyptic number.

It is an amenable number.

14114055242433 is a deficient number, since it is larger than the sum of its proper divisors (4704685080815).

14114055242433 is an equidigital number, since it uses as much as digits as its factorization.

14114055242433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4704685080814.

The product of its (nonzero) digits is 230400, while the sum is 39.

The spelling of 14114055242433 in words is "fourteen trillion, one hundred fourteen billion, fifty-five million, two hundred forty-two thousand, four hundred thirty-three".