Base | Representation |
---|---|
bin | 1100110101100011001000… |
… | …0110001111011010001011 |
3 | 1211222021222002220112010211 |
4 | 3031120302012033122023 |
5 | 3322221140334001220 |
6 | 50003532431021551 |
7 | 2654465426203561 |
oct | 315306206173213 |
9 | 54867862815124 |
10 | 14114103031435 |
11 | 4551837230a70 |
12 | 16bb4a866a8b7 |
13 | 7b4c53507ab4 |
14 | 36b1aa545a31 |
15 | 19721831db5a |
hex | cd63218f68b |
14114103031435 has 16 divisors (see below), whose sum is σ = 18559498890240. Its totient is φ = 10218771692640.
The previous prime is 14114103031423. The next prime is 14114103031451. The reversal of 14114103031435 is 53413030141141.
14114103031435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14114103031435 - 213 = 14114103023243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14114103031397 and 14114103031406.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 575369025 + ... + 575393554.
It is an arithmetic number, because the mean of its divisors is an integer number (1159968680640).
Almost surely, 214114103031435 is an apocalyptic number.
14114103031435 is a deficient number, since it is larger than the sum of its proper divisors (4445395858805).
14114103031435 is a wasteful number, since it uses less digits than its factorization.
14114103031435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1150762818.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 14114103031435 its reverse (53413030141141), we get a palindrome (67527133172576).
The spelling of 14114103031435 in words is "fourteen trillion, one hundred fourteen billion, one hundred three million, thirty-one thousand, four hundred thirty-five".
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