141141440400113 has 8 divisors (see below), whose sum is σ = 141970943815680. Its totient is φ = 140312880141120.

The previous prime is 141141440400049. The next prime is 141141440400209. The reversal of 141141440400113 is 311004044141141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141141440400113 - 2⁶ = 141141440400049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (141141440400713) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 235488968 + ... + 236087561.

It is an arithmetic number, because the mean of its divisors is an integer number (17746367976960).

Almost surely, 2^{141141440400113} is an apocalyptic number.

It is an amenable number.

141141440400113 is a deficient number, since it is larger than the sum of its proper divisors (829503415567).

141141440400113 is a wasteful number, since it uses less digits than its factorization.

141141440400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471578287.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 141141440400113 its reverse (311004044141141), we get a palindrome (452145484541254).

The spelling of 141141440400113 in words is "one hundred forty-one trillion, one hundred forty-one billion, four hundred forty million, four hundred thousand, one hundred thirteen".