141142232011331 has 8 divisors (see below), whose sum is σ = 146414911876800. Its totient is φ = 135956703879360.

The previous prime is 141142232011273. The next prime is 141142232011351. The reversal of 141142232011331 is 133110232241141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141142232011331 - 2⁶ = 141142232011267 is a prime.

It is a super-3 number, since 3×141142232011331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141142232011294 and 141142232011303.

It is not an unprimeable number, because it can be changed into a prime (141142232011351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21787930076 + ... + 21787936553.

It is an arithmetic number, because the mean of its divisors is an integer number (18301863984600).

Almost surely, 2^{141142232011331} is an apocalyptic number.

141142232011331 is a deficient number, since it is larger than the sum of its proper divisors (5272679865469).

141142232011331 is an equidigital number, since it uses as much as digits as its factorization.

141142232011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43575866749.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 141142232011331 its reverse (133110232241141), we get a palindrome (274252464252472).

The spelling of 141142232011331 in words is "one hundred forty-one trillion, one hundred forty-two billion, two hundred thirty-two million, eleven thousand, three hundred thirty-one".