14114233230131 has 4 divisors (see below), whose sum is σ = 14114920041264. Its totient is φ = 14113546419000.

The previous prime is 14114233230121. The next prime is 14114233230137. The reversal of 14114233230131 is 13103233241141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14114233230131 - 2⁶ = 14114233230067 is a prime.

It is a super-2 number, since 2×14114233230131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14114233230094 and 14114233230103.

It is not an unprimeable number, because it can be changed into a prime (14114233230137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343374740 + ... + 343415841.

It is an arithmetic number, because the mean of its divisors is an integer number (3528730010316).

Almost surely, 2^{14114233230131} is an apocalyptic number.

14114233230131 is a deficient number, since it is larger than the sum of its proper divisors (686811133).

14114233230131 is an equidigital number, since it uses as much as digits as its factorization.

14114233230131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 686811132.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 14114233230131 its reverse (13103233241141), we get a palindrome (27217466471272).

The spelling of 14114233230131 in words is "fourteen trillion, one hundred fourteen billion, two hundred thirty-three million, two hundred thirty thousand, one hundred thirty-one".