Base | Representation |
---|---|
bin | 100000000101111010101101… |
… | …110110011111010100000011 |
3 | 200111202020200020111101112212 |
4 | 200011322231312133110003 |
5 | 122000001140244223210 |
6 | 1220104415155012335 |
7 | 41505220112030243 |
oct | 4005725566372403 |
9 | 614666606441485 |
10 | 141144132023555 |
11 | 40a779879a8781 |
12 | 139b681829a0ab |
13 | 609aab063647b |
14 | 26bd5aba41b23 |
15 | 114b7395c7805 |
hex | 805eadd9f503 |
141144132023555 has 16 divisors (see below), whose sum is σ = 175266196891200. Its totient is φ = 108988826271360.
The previous prime is 141144132023441. The next prime is 141144132023561. The reversal of 141144132023555 is 555320231441141.
141144132023555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 141144132023555 - 212 = 141144132019459 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 146160476 + ... + 147122985.
It is an arithmetic number, because the mean of its divisors is an integer number (10954137305700).
Almost surely, 2141144132023555 is an apocalyptic number.
141144132023555 is a deficient number, since it is larger than the sum of its proper divisors (34122064867645).
141144132023555 is a wasteful number, since it uses less digits than its factorization.
141144132023555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 293286814.
The product of its (nonzero) digits is 288000, while the sum is 41.
Adding to 141144132023555 its reverse (555320231441141), we get a palindrome (696464363464696).
The spelling of 141144132023555 in words is "one hundred forty-one trillion, one hundred forty-four billion, one hundred thirty-two million, twenty-three thousand, five hundred fifty-five".
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