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141144250051 = 7227509104711
BaseRepresentation
bin1000001101110011011…
…0100101011011000011
3111111022120210210201201
42003130312211123003
54303030412000201
6144501335042031
713124454221200
oct2033466453303
9444276723651
10141144250051
115494a282142
1223430b10317
1310404966b2c
146b8d5a8ca7
153a113e8801
hex20dcda56c3

141144250051 has 12 divisors (see below), whose sum is σ = 164195745840. Its totient is φ = 120975232560.

The previous prime is 141144249989. The next prime is 141144250063. The reversal of 141144250051 is 150052441141.

141144250051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 141144250051 - 227 = 141010032323 is a prime.

It is not an unprimeable number, because it can be changed into a prime (141144250081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1295586 + ... + 1400296.

It is an arithmetic number, because the mean of its divisors is an integer number (13682978820).

Almost surely, 2141144250051 is an apocalyptic number.

141144250051 is a deficient number, since it is larger than the sum of its proper divisors (23051495789).

141144250051 is a wasteful number, since it uses less digits than its factorization.

141144250051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132234 (or 132227 counting only the distinct ones).

The product of its (nonzero) digits is 3200, while the sum is 28.

Adding to 141144250051 its reverse (150052441141), we get a palindrome (291196691192).

The spelling of 141144250051 in words is "one hundred forty-one billion, one hundred forty-four million, two hundred fifty thousand, fifty-one".

Divisors: 1 7 49 27509 104711 192563 732977 1347941 5130839 2880494899 20163464293 141144250051