1411453405553 has 4 divisors (see below), whose sum is σ = 1411457480820. Its totient is φ = 1411449330288.

The previous prime is 1411453405501. The next prime is 1411453405577. The reversal of 1411453405553 is 3555043541141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 541007323024 + 870446082529 = 735532^2 + 932977^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411453405553 - 2³⁰ = 1410379663729 is a prime.

It is a super-2 number, since 2×1411453405553² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1411453405553.

It is not an unprimeable number, because it can be changed into a prime (1411453405253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1464350 + ... + 2228727.

It is an arithmetic number, because the mean of its divisors is an integer number (352864370205).

Almost surely, 2^{1411453405553} is an apocalyptic number.

It is an amenable number.

1411453405553 is a deficient number, since it is larger than the sum of its proper divisors (4075267).

1411453405553 is an equidigital number, since it uses as much as digits as its factorization.

1411453405553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4075266.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 1411453405553 its reverse (3555043541141), we get a palindrome (4966496946694).

The spelling of 1411453405553 in words is "one trillion, four hundred eleven billion, four hundred fifty-three million, four hundred five thousand, five hundred fifty-three".