Base | Representation |
---|---|
bin | 1100110101100100110011… |
… | …1000000100100110110011 |
3 | 1211222100010102021211111111 |
4 | 3031121030320010212303 |
5 | 3322223100342131003 |
6 | 50004045200254151 |
7 | 2654512523014366 |
oct | 315311470044663 |
9 | 54870112254444 |
10 | 14114552302003 |
11 | 4551a4789965a |
12 | 16bb5b3011357 |
13 | 7b4cc560a77a |
14 | 36b2100940dd |
15 | 1972429b5e6d |
hex | cd64ce049b3 |
14114552302003 has 4 divisors (see below), whose sum is σ = 14175129779928. Its totient is φ = 14053974824080.
The previous prime is 14114552301959. The next prime is 14114552302021. The reversal of 14114552302003 is 30020325541141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14114552302003 - 29 = 14114552301491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14114552302033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30288738613 + ... + 30288739078.
It is an arithmetic number, because the mean of its divisors is an integer number (3543782444982).
Almost surely, 214114552302003 is an apocalyptic number.
14114552302003 is a deficient number, since it is larger than the sum of its proper divisors (60577477925).
14114552302003 is an equidigital number, since it uses as much as digits as its factorization.
14114552302003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60577477924.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14114552302003 its reverse (30020325541141), we get a palindrome (44134877843144).
The spelling of 14114552302003 in words is "fourteen trillion, one hundred fourteen billion, five hundred fifty-two million, three hundred two thousand, three".
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