Base | Representation |
---|---|
bin | 1100110101100101000101… |
… | …0010001011001011110011 |
3 | 1211222100022120102221221212 |
4 | 3031121101102023023303 |
5 | 3322223223310103210 |
6 | 50004100401310335 |
7 | 2654514411416522 |
oct | 315312122131363 |
9 | 54870276387855 |
10 | 14114626253555 |
11 | 4551a85609543 |
12 | 16bb6139353ab |
13 | 7b5007a30a99 |
14 | 36b219c244b9 |
15 | 197249222805 |
hex | cd65148b2f3 |
14114626253555 has 8 divisors (see below), whose sum is σ = 16937684118672. Its totient is φ = 11291612593248.
The previous prime is 14114626253549. The next prime is 14114626253573. The reversal of 14114626253555 is 55535262641141.
14114626253555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14114626253555 - 242 = 9716579742451 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10344632 + ... + 11629301.
It is an arithmetic number, because the mean of its divisors is an integer number (2117210514834).
Almost surely, 214114626253555 is an apocalyptic number.
14114626253555 is a deficient number, since it is larger than the sum of its proper divisors (2823057865117).
14114626253555 is a wasteful number, since it uses less digits than its factorization.
14114626253555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22102405.
The product of its digits is 4320000, while the sum is 50.
Adding to 14114626253555 its reverse (55535262641141), we get a palindrome (69649888894696).
The spelling of 14114626253555 in words is "fourteen trillion, one hundred fourteen billion, six hundred twenty-six million, two hundred fifty-three thousand, five hundred fifty-five".
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