Base | Representation |
---|---|
bin | 10100100010100100110… |
… | …000010011110011101011 |
3 | 11222221100210111010212122 |
4 | 110202210300103303223 |
5 | 141111234412304210 |
6 | 3000235034501455 |
7 | 203656421641346 |
oct | 24424460236353 |
9 | 4887323433778 |
10 | 1411513400555 |
11 | 4a468a575565 |
12 | 1a9688b9488b |
13 | a3149cc8c1b |
14 | 4c46375d45d |
15 | 26ab3d12b55 |
hex | 148a4c13ceb |
1411513400555 has 4 divisors (see below), whose sum is σ = 1693816080672. Its totient is φ = 1129210720440.
The previous prime is 1411513400513. The next prime is 1411513400587. The reversal of 1411513400555 is 5550043151141.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1411513400555 - 28 = 1411513400299 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141151340051 + ... + 141151340060.
It is an arithmetic number, because the mean of its divisors is an integer number (423454020168).
Almost surely, 21411513400555 is an apocalyptic number.
1411513400555 is a deficient number, since it is larger than the sum of its proper divisors (282302680117).
1411513400555 is an equidigital number, since it uses as much as digits as its factorization.
1411513400555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 282302680116.
The product of its (nonzero) digits is 30000, while the sum is 35.
Adding to 1411513400555 its reverse (5550043151141), we get a palindrome (6961556551696).
The spelling of 1411513400555 in words is "one trillion, four hundred eleven billion, five hundred thirteen million, four hundred thousand, five hundred fifty-five".
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