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141200002330041 = 347066667443347
BaseRepresentation
bin100000000110101110101111…
…111110110010110110111001
3200111221120212221100000210110
4200012232233332302312321
5122001410101044030131
61220150215141334533
741512235454555204
oct4006565776626671
9614846787300713
10141200002330041
1140a99648269996
1213a0560b107449
1360a3145632b15
1426c218bc6093b
15114ce094d7646
hex806baffb2db9

141200002330041 has 4 divisors (see below), whose sum is σ = 188266669773392. Its totient is φ = 94133334886692.

The previous prime is 141200002330039. The next prime is 141200002330061. The reversal of 141200002330041 is 140033200002141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 141200002330041 - 21 = 141200002330039 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (141200002330061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23533333721671 + ... + 23533333721676.

It is an arithmetic number, because the mean of its divisors is an integer number (47066667443348).

Almost surely, 2141200002330041 is an apocalyptic number.

It is an amenable number.

141200002330041 is a deficient number, since it is larger than the sum of its proper divisors (47066667443351).

141200002330041 is an equidigital number, since it uses as much as digits as its factorization.

141200002330041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47066667443350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 141200002330041 its reverse (140033200002141), we get a palindrome (281233202332182).

The spelling of 141200002330041 in words is "one hundred forty-one trillion, two hundred billion, two million, three hundred thirty thousand, forty-one".

Divisors: 1 3 47066667443347 141200002330041