Base | Representation |
---|---|
bin | 11010010011001111… |
… | …00111110111010001 |
3 | 1100110001022121200101 |
4 | 31021213213313101 |
5 | 212404211304203 |
6 | 10253041052401 |
7 | 1006623144154 |
oct | 151147476721 |
9 | 40401277611 |
10 | 14120025553 |
11 | 5a96428207 |
12 | 28a0927101 |
13 | 144044460a |
14 | 97d3dbc9b |
15 | 57994141d |
hex | 3499e7dd1 |
14120025553 has 12 divisors (see below), whose sum is σ = 14459064448. Its totient is φ = 13788264600.
The previous prime is 14120025551. The next prime is 14120025559. The reversal of 14120025553 is 35552002141.
It is not a de Polignac number, because 14120025553 - 21 = 14120025551 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14120025551) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 512200 + ... + 539062.
Almost surely, 214120025553 is an apocalyptic number.
It is an amenable number.
14120025553 is a deficient number, since it is larger than the sum of its proper divisors (339038895).
14120025553 is an equidigital number, since it uses as much as digits as its factorization.
14120025553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27132 (or 27073 counting only the distinct ones).
The product of its (nonzero) digits is 6000, while the sum is 28.
Adding to 14120025553 its reverse (35552002141), we get a palindrome (49672027694).
It can be divided in two parts, 141200 and 25553, that added together give a triangular number (166753 = T577).
The spelling of 14120025553 in words is "fourteen billion, one hundred twenty million, twenty-five thousand, five hundred fifty-three".
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