Base | Representation |
---|---|
bin | 11010010011001111… |
… | …11110000010001011 |
3 | 1100110001111020020201 |
4 | 31021213332002023 |
5 | 212404222210423 |
6 | 10253043033031 |
7 | 1006624003003 |
oct | 151147760213 |
9 | 40401436221 |
10 | 14120116363 |
11 | 5a9648a461 |
12 | 28a096b777 |
13 | 1440476a52 |
14 | 97d423003 |
15 | 57995d2ad |
hex | 3499fe08b |
14120116363 has 4 divisors (see below), whose sum is σ = 14121067608. Its totient is φ = 14119165120.
The previous prime is 14120116319. The next prime is 14120116447. The reversal of 14120116363 is 36361102141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120116363 is a prime.
It is a super-2 number, since 2×141201163632 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14120116303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 452998 + ... + 483163.
It is an arithmetic number, because the mean of its divisors is an integer number (3530266902).
Almost surely, 214120116363 is an apocalyptic number.
14120116363 is a deficient number, since it is larger than the sum of its proper divisors (951245).
14120116363 is an equidigital number, since it uses as much as digits as its factorization.
14120116363 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 951244.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 14120116363 in words is "fourteen billion, one hundred twenty million, one hundred sixteen thousand, three hundred sixty-three".
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