Base | Representation |
---|---|
bin | 11010010011001111… |
… | …11111001011011011 |
3 | 1100110001111110200100 |
4 | 31021213333023123 |
5 | 212404222333201 |
6 | 10253043110443 |
7 | 1006624022451 |
oct | 151147771333 |
9 | 40401443610 |
10 | 14120121051 |
11 | 5a96492a33 |
12 | 28a0972423 |
13 | 1440478c1a |
14 | 97d4249d1 |
15 | 57995e886 |
hex | 3499ff2db |
14120121051 has 6 divisors (see below), whose sum is σ = 20395730420. Its totient is φ = 9413414028.
The previous prime is 14120121031. The next prime is 14120121097. The reversal of 14120121051 is 15012102141.
It is not a de Polignac number, because 14120121051 - 225 = 14086566619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14120121031) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 784451161 + ... + 784451178.
Almost surely, 214120121051 is an apocalyptic number.
14120121051 is a deficient number, since it is larger than the sum of its proper divisors (6275609369).
14120121051 is a wasteful number, since it uses less digits than its factorization.
14120121051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1568902345 (or 1568902342 counting only the distinct ones).
The product of its (nonzero) digits is 80, while the sum is 18.
Adding to 14120121051 its reverse (15012102141), we get a palindrome (29132223192).
The spelling of 14120121051 in words is "fourteen billion, one hundred twenty million, one hundred twenty-one thousand, fifty-one".
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