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14120135201 = 26353688727
BaseRepresentation
bin11010010011010000…
…00010101000100001
31100110001112012002102
431021220002220201
5212404223311301
610253043300145
71006624111634
oct151150025041
940401465072
1014120135201
115a964a2627
1228a097a655
1314404824b3
1497d429c1b
15579963b6b
hex349a02a21

14120135201 has 4 divisors (see below), whose sum is σ = 14173824192. Its totient is φ = 14066446212.

The previous prime is 14120135149. The next prime is 14120135203. The reversal of 14120135201 is 10253102141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14120135201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14120135203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26844101 + ... + 26844626.

It is an arithmetic number, because the mean of its divisors is an integer number (3543456048).

Almost surely, 214120135201 is an apocalyptic number.

It is an amenable number.

14120135201 is a deficient number, since it is larger than the sum of its proper divisors (53688991).

14120135201 is an equidigital number, since it uses as much as digits as its factorization.

14120135201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53688990.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 14120135201 its reverse (10253102141), we get a palindrome (24373237342).

The spelling of 14120135201 in words is "fourteen billion, one hundred twenty million, one hundred thirty-five thousand, two hundred one".

Divisors: 1 263 53688727 14120135201