Base | Representation |
---|---|
bin | 11010010011010000… |
… | …00010101000100001 |
3 | 1100110001112012002102 |
4 | 31021220002220201 |
5 | 212404223311301 |
6 | 10253043300145 |
7 | 1006624111634 |
oct | 151150025041 |
9 | 40401465072 |
10 | 14120135201 |
11 | 5a964a2627 |
12 | 28a097a655 |
13 | 14404824b3 |
14 | 97d429c1b |
15 | 579963b6b |
hex | 349a02a21 |
14120135201 has 4 divisors (see below), whose sum is σ = 14173824192. Its totient is φ = 14066446212.
The previous prime is 14120135149. The next prime is 14120135203. The reversal of 14120135201 is 10253102141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120135201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14120135203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26844101 + ... + 26844626.
It is an arithmetic number, because the mean of its divisors is an integer number (3543456048).
Almost surely, 214120135201 is an apocalyptic number.
It is an amenable number.
14120135201 is a deficient number, since it is larger than the sum of its proper divisors (53688991).
14120135201 is an equidigital number, since it uses as much as digits as its factorization.
14120135201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53688990.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 14120135201 its reverse (10253102141), we get a palindrome (24373237342).
The spelling of 14120135201 in words is "fourteen billion, one hundred twenty million, one hundred thirty-five thousand, two hundred one".
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