141202234320043 has 4 divisors (see below), whose sum is σ = 152063944652368. Its totient is φ = 130340523987720.

The previous prime is 141202234320023. The next prime is 141202234320109. The reversal of 141202234320043 is 340023432202141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141202234320043 - 2²⁵ = 141202200765611 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141202234319987 and 141202234320014.

It is not an unprimeable number, because it can be changed into a prime (141202234320023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5430855166143 + ... + 5430855166168.

It is an arithmetic number, because the mean of its divisors is an integer number (38015986163092).

Almost surely, 2^{141202234320043} is an apocalyptic number.

141202234320043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

141202234320043 is a deficient number, since it is larger than the sum of its proper divisors (10861710332325).

141202234320043 is a wasteful number, since it uses less digits than its factorization.

141202234320043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10861710332324.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 141202234320043 its reverse (340023432202141), we get a palindrome (481225666522184).

The spelling of 141202234320043 in words is "one hundred forty-one trillion, two hundred two billion, two hundred thirty-four million, three hundred twenty thousand, forty-three".