141202241004033 has 16 divisors (see below), whose sum is σ = 228205642027200. Its totient is φ = 85577115759840.

The previous prime is 141202241003987. The next prime is 141202241004037. The reversal of 141202241004033 is 330400142202141.

141202241004033 is a `hidden beast` number, since 1 + 4 + 1 + 20 + 224 + 10 + 0 + 403 + 3 = 666.

It is not a de Polignac number, because 141202241004033 - 2¹⁶ = 141202240938497 is a prime.

It is a super-3 number, since 3×141202241004033³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 141202241003988 and 141202241004006.

It is not an unprimeable number, because it can be changed into a prime (141202241004037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 237714210148 + ... + 237714210741.

It is an arithmetic number, because the mean of its divisors is an integer number (14262852626700).

Almost surely, 2^{141202241004033} is an apocalyptic number.

It is an amenable number.

141202241004033 is a deficient number, since it is larger than the sum of its proper divisors (87003401023167).

141202241004033 is a wasteful number, since it uses less digits than its factorization.

141202241004033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 475428420909 (or 475428420903 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 141202241004033 its reverse (330400142202141), we get a palindrome (471602383206174).

The spelling of 141202241004033 in words is "one hundred forty-one trillion, two hundred two billion, two hundred forty-one million, four thousand, thirty-three".