Base | Representation |
---|---|
bin | 11010010011010000… |
… | …11100101111010011 |
3 | 1100110001201121202210 |
4 | 31021220130233103 |
5 | 212404240222011 |
6 | 10253045443203 |
7 | 1006625035452 |
oct | 151150345723 |
9 | 40401647683 |
10 | 14120242131 |
11 | 5a965659a6 |
12 | 28a0a10503 |
13 | 14404bc078 |
14 | 97d456b99 |
15 | 5799856a6 |
hex | 349a1cbd3 |
14120242131 has 8 divisors (see below), whose sum is σ = 18828917200. Its totient is φ = 9412530912.
The previous prime is 14120242127. The next prime is 14120242151. The reversal of 14120242131 is 13124202141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14120242131 - 22 = 14120242127 is a prime.
It is a super-2 number, since 2×141202421312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14120242098 and 14120242107.
It is not an unprimeable number, because it can be changed into a prime (14120242151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 206056 + ... + 265893.
It is an arithmetic number, because the mean of its divisors is an integer number (2353614650).
Almost surely, 214120242131 is an apocalyptic number.
14120242131 is a deficient number, since it is larger than the sum of its proper divisors (4708675069).
14120242131 is an equidigital number, since it uses as much as digits as its factorization.
14120242131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 481925.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 14120242131 its reverse (13124202141), we get a palindrome (27244444272).
The spelling of 14120242131 in words is "fourteen billion, one hundred twenty million, two hundred forty-two thousand, one hundred thirty-one".
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