Base | Representation |
---|---|
bin | 100000000110110001101010… |
… | …100110010001001110110011 |
3 | 200111221212222010200202011120 |
4 | 200012301222212101032303 |
5 | 122001433004102141433 |
6 | 1220151453543513323 |
7 | 41512406163062244 |
oct | 4006615246211663 |
9 | 614855863622146 |
10 | 141203133240243 |
11 | 40a9aa04613088 |
12 | 13a06143758843 |
13 | 60a35241911c9 |
14 | 26c23a79c2ccb |
15 | 114d03e2d97b3 |
hex | 806c6a9913b3 |
141203133240243 has 4 divisors (see below), whose sum is σ = 188270844320328. Its totient is φ = 94135422160160.
The previous prime is 141203133240227. The next prime is 141203133240271. The reversal of 141203133240243 is 342042331302141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141203133240243 - 24 = 141203133240227 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141203133240223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23533855540038 + ... + 23533855540043.
It is an arithmetic number, because the mean of its divisors is an integer number (47067711080082).
Almost surely, 2141203133240243 is an apocalyptic number.
141203133240243 is a deficient number, since it is larger than the sum of its proper divisors (47067711080085).
141203133240243 is an equidigital number, since it uses as much as digits as its factorization.
141203133240243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47067711080084.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 141203133240243 its reverse (342042331302141), we get a palindrome (483245464542384).
The spelling of 141203133240243 in words is "one hundred forty-one trillion, two hundred three billion, one hundred thirty-three million, two hundred forty thousand, two hundred forty-three".
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