Base | Representation |
---|---|
bin | 100000000110111001010010… |
… | …000011001011010010000011 |
3 | 200111222200002002012100122111 |
4 | 200012321102003023102003 |
5 | 122002101231144302433 |
6 | 1220155325244320151 |
7 | 41513115635452021 |
oct | 4006712203132203 |
9 | 614880062170574 |
10 | 141211311322243 |
11 | 40aa3420963138 |
12 | 13a07846543057 |
13 | 60a4228586196 |
14 | 26c2941ba5711 |
15 | 114d36c25edcd |
hex | 806e520cb483 |
141211311322243 has 4 divisors (see below), whose sum is σ = 141211409591728. Its totient is φ = 141211213052760.
The previous prime is 141211311322189. The next prime is 141211311322259. The reversal of 141211311322243 is 342223113112141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141211311322243 - 237 = 141073872368771 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141211311322043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46946796 + ... + 49864057.
It is an arithmetic number, because the mean of its divisors is an integer number (35302852397932).
Almost surely, 2141211311322243 is an apocalyptic number.
141211311322243 is a deficient number, since it is larger than the sum of its proper divisors (98269485).
141211311322243 is an equidigital number, since it uses as much as digits as its factorization.
141211311322243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98269484.
The product of its digits is 6912, while the sum is 31.
Adding to 141211311322243 its reverse (342223113112141), we get a palindrome (483434424434384).
The spelling of 141211311322243 in words is "one hundred forty-one trillion, two hundred eleven billion, three hundred eleven million, three hundred twenty-two thousand, two hundred forty-three".
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