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141212412113 = 1125712544409
BaseRepresentation
bin1000001110000011101…
…0100110100011010001
3111111111100001210111112
42003200322212203101
54303200334141423
6144512212023105
713126242461333
oct2034072464321
9444440053445
10141212412113
11549847a8323
122344b901a95
1310415b10c06
146b9866d453
153a173aea78
hex20e0ea68d1

141212412113 has 4 divisors (see below), whose sum is σ = 141224967780. Its totient is φ = 141199856448.

The previous prime is 141212412101. The next prime is 141212412137. The reversal of 141212412113 is 311214212141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 46808620609 + 94403791504 = 216353^2 + 307252^2 .

It is a cyclic number.

It is not a de Polignac number, because 141212412113 - 222 = 141208217809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141212412163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6260948 + ... + 6283461.

It is an arithmetic number, because the mean of its divisors is an integer number (35306241945).

Almost surely, 2141212412113 is an apocalyptic number.

It is an amenable number.

141212412113 is a deficient number, since it is larger than the sum of its proper divisors (12555667).

141212412113 is a wasteful number, since it uses less digits than its factorization.

141212412113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12555666.

The product of its digits is 384, while the sum is 23.

Adding to 141212412113 its reverse (311214212141), we get a palindrome (452426624254).

The spelling of 141212412113 in words is "one hundred forty-one billion, two hundred twelve million, four hundred twelve thousand, one hundred thirteen".

Divisors: 1 11257 12544409 141212412113