Base | Representation |
---|---|
bin | 100000000110111011010110… |
… | …011111011101111011100011 |
3 | 200111222212210221022002212110 |
4 | 200012323112133131323203 |
5 | 122002120304013044141 |
6 | 1220200333541530403 |
7 | 41513224666305120 |
oct | 4006732637357343 |
9 | 614885727262773 |
10 | 141213533331171 |
11 | 40aa4361155354 |
12 | 13a08166713a03 |
13 | 60a44c0a22472 |
14 | 26c2ab2d31747 |
15 | 114d44c377e16 |
hex | 806ed67ddee3 |
141213533331171 has 8 divisors (see below), whose sum is σ = 215182526980864. Its totient is φ = 80693447617800.
The previous prime is 141213533331161. The next prime is 141213533331197. The reversal of 141213533331171 is 171133335312141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 141213533331171 - 211 = 141213533329123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141213533331161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3362226984055 + ... + 3362226984096.
It is an arithmetic number, because the mean of its divisors is an integer number (26897815872608).
Almost surely, 2141213533331171 is an apocalyptic number.
141213533331171 is a deficient number, since it is larger than the sum of its proper divisors (73968993649693).
141213533331171 is an equidigital number, since it uses as much as digits as its factorization.
141213533331171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6724453968161.
The product of its digits is 68040, while the sum is 39.
The spelling of 141213533331171 in words is "one hundred forty-one trillion, two hundred thirteen billion, five hundred thirty-three million, three hundred thirty-one thousand, one hundred seventy-one".
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