1412141322041 has 4 divisors (see below), whose sum is σ = 1412192335092. Its totient is φ = 1412090308992.

The previous prime is 1412141322037. The next prime is 1412141322083. The reversal of 1412141322041 is 1402231412141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 419089211641 + 993052110400 = 647371^2 + 996520^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412141322041 - 2² = 1412141322037 is a prime.

It is a super-2 number, since 2×1412141322041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1412141322041.

It is not an unprimeable number, because it can be changed into a prime (1412141322091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25464980 + ... + 25520373.

It is an arithmetic number, because the mean of its divisors is an integer number (353048083773).

Almost surely, 2^{1412141322041} is an apocalyptic number.

It is an amenable number.

1412141322041 is a deficient number, since it is larger than the sum of its proper divisors (51013051).

1412141322041 is an equidigital number, since it uses as much as digits as its factorization.

1412141322041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51013050.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 1412141322041 its reverse (1402231412141), we get a palindrome (2814372734182).

The spelling of 1412141322041 in words is "one trillion, four hundred twelve billion, one hundred forty-one million, three hundred twenty-two thousand, forty-one".