Base | Representation |
---|---|
bin | 1100110110000001010101… |
… | …1000001010010011010001 |
3 | 1212000001220011201022202111 |
4 | 3031200111120022103101 |
5 | 3322334242021440213 |
6 | 50011353151345321 |
7 | 2655203361643636 |
oct | 315402530122321 |
9 | 55001804638674 |
10 | 14122211124433 |
11 | 4555218018275 |
12 | 1700b8bb22241 |
13 | 7b5946266269 |
14 | 36b73930a18d |
15 | 19754006ba3d |
hex | cd81560a4d1 |
14122211124433 has 16 divisors (see below), whose sum is σ = 14964956928000. Its totient is φ = 13289424613200.
The previous prime is 14122211124431. The next prime is 14122211124443. The reversal of 14122211124433 is 33442111222141.
It is a cyclic number.
It is not a de Polignac number, because 14122211124433 - 21 = 14122211124431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14122211124395 and 14122211124404.
It is not an unprimeable number, because it can be changed into a prime (14122211124431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43731960 + ... + 44053702.
It is an arithmetic number, because the mean of its divisors is an integer number (935309808000).
Almost surely, 214122211124433 is an apocalyptic number.
It is an amenable number.
14122211124433 is a deficient number, since it is larger than the sum of its proper divisors (842745803567).
14122211124433 is a wasteful number, since it uses less digits than its factorization.
14122211124433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 337212.
The product of its digits is 9216, while the sum is 31.
Adding to 14122211124433 its reverse (33442111222141), we get a palindrome (47564322346574).
The spelling of 14122211124433 in words is "fourteen trillion, one hundred twenty-two billion, two hundred eleven million, one hundred twenty-four thousand, four hundred thirty-three".
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