Base | Representation |
---|---|
bin | 11010010011100000… |
… | …00010111001101011 |
3 | 1100110012110210100101 |
4 | 31021300002321223 |
5 | 212410242432301 |
6 | 10253200250231 |
7 | 1006651001164 |
oct | 151160027153 |
9 | 40405423311 |
10 | 14122233451 |
11 | 5a976a6017 |
12 | 28a1610977 |
13 | 1440a38571 |
14 | 97d81476b |
15 | 579c2a701 |
hex | 349c02e6b |
14122233451 has 4 divisors (see below), whose sum is σ = 14361593400. Its totient is φ = 13882873504.
The previous prime is 14122233449. The next prime is 14122233497. The reversal of 14122233451 is 15433222141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15433222141 = 3023 ⋅5105267.
It is a cyclic number.
It is not a de Polignac number, because 14122233451 - 21 = 14122233449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14122236451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119679886 + ... + 119680003.
It is an arithmetic number, because the mean of its divisors is an integer number (3590398350).
Almost surely, 214122233451 is an apocalyptic number.
14122233451 is a deficient number, since it is larger than the sum of its proper divisors (239359949).
14122233451 is an equidigital number, since it uses as much as digits as its factorization.
14122233451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239359948.
The product of its digits is 5760, while the sum is 28.
Adding to 14122233451 its reverse (15433222141), we get a palindrome (29555455592).
The spelling of 14122233451 in words is "fourteen billion, one hundred twenty-two million, two hundred thirty-three thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •