Base | Representation |
---|---|
bin | 1100110110000110010101… |
… | …0011100111010111100011 |
3 | 1212000012100122000110012111 |
4 | 3031201211103213113203 |
5 | 3322400013320010201 |
6 | 50012134213340151 |
7 | 2655251534065666 |
oct | 315414523472743 |
9 | 55005318013174 |
10 | 14123552110051 |
11 | 4555845a6964a |
12 | 17012a5037657 |
13 | 7b5acb021587 |
14 | 36b8254596dd |
15 | 1975bcb55b51 |
hex | cd8654e75e3 |
14123552110051 has 4 divisors (see below), whose sum is σ = 14123789647912. Its totient is φ = 14123314572192.
The previous prime is 14123552110049. The next prime is 14123552110069. The reversal of 14123552110051 is 15001125532141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14123552110051 - 21 = 14123552110049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14123552109995 and 14123552110022.
It is not an unprimeable number, because it can be changed into a prime (14123552110001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118679721 + ... + 118798666.
It is an arithmetic number, because the mean of its divisors is an integer number (3530947411978).
Almost surely, 214123552110051 is an apocalyptic number.
14123552110051 is a deficient number, since it is larger than the sum of its proper divisors (237537861).
14123552110051 is an equidigital number, since it uses as much as digits as its factorization.
14123552110051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237537860.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 14123552110051 its reverse (15001125532141), we get a palindrome (29124677642192).
The spelling of 14123552110051 in words is "fourteen trillion, one hundred twenty-three billion, five hundred fifty-two million, one hundred ten thousand, fifty-one".
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