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14123552233 = 72017650319
BaseRepresentation
bin11010010011101010…
…00100110111101001
31100110021221210101011
431021311010313221
5212411112132413
610253244423521
71006665133060
oct151165046751
940407853334
1014123552233
115a9841691a
1228a1b47ba1
1314410aa8cb
1497da791d7
15579ddb33d
hex349d44de9

14123552233 has 4 divisors (see below), whose sum is σ = 16141202560. Its totient is φ = 12105901908.

The previous prime is 14123552197. The next prime is 14123552243. The reversal of 14123552233 is 33225532141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33225532141 = 227146367983.

It is a cyclic number.

It is not a de Polignac number, because 14123552233 - 221 = 14121455081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14123552195 and 14123552204.

It is not an unprimeable number, because it can be changed into a prime (14123552243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1008825153 + ... + 1008825166.

It is an arithmetic number, because the mean of its divisors is an integer number (4035300640).

Almost surely, 214123552233 is an apocalyptic number.

It is an amenable number.

14123552233 is a deficient number, since it is larger than the sum of its proper divisors (2017650327).

14123552233 is an equidigital number, since it uses as much as digits as its factorization.

14123552233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2017650326.

The product of its digits is 21600, while the sum is 31.

The spelling of 14123552233 in words is "fourteen billion, one hundred twenty-three million, five hundred fifty-two thousand, two hundred thirty-three".

Divisors: 1 7 2017650319 14123552233