14124011331 has 4 divisors (see below), whose sum is σ = 18832015112. Its totient is φ = 9416007552.

The previous prime is 14124011303. The next prime is 14124011347. The reversal of 14124011331 is 13311042141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14124011331 - 2⁶ = 14124011267 is a prime.

It is a super-3 number, since 3×14124011331³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14124011298 and 14124011307.

It is not an unprimeable number, because it can be changed into a prime (14124011351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2354001886 + ... + 2354001891.

It is an arithmetic number, because the mean of its divisors is an integer number (4708003778).

Almost surely, 2^14124011331 is an apocalyptic number.

14124011331 is a deficient number, since it is larger than the sum of its proper divisors (4708003781).

14124011331 is an equidigital number, since it uses as much as digits as its factorization.

14124011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4708003780.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 14124011331 its reverse (13311042141), we get a palindrome (27435053472).

The spelling of 14124011331 in words is "fourteen billion, one hundred twenty-four million, eleven thousand, three hundred thirty-one".