Base | Representation |
---|---|
bin | 1100110110001000011010… |
… | …1000110000101100111001 |
3 | 1212000020210121020022120102 |
4 | 3031202012220300230321 |
5 | 3322402134443121213 |
6 | 50012305511005145 |
7 | 2655301434121400 |
oct | 315420650605471 |
9 | 55006717208512 |
10 | 14124111301433 |
11 | 4556002684391 |
12 | 17014203697b5 |
13 | 7b5b89b2c553 |
14 | 36b87981c637 |
15 | 197601cb2158 |
hex | cd886a30b39 |
14124111301433 has 12 divisors (see below), whose sum is σ = 16432324157952. Its totient is φ = 12104733904200.
The previous prime is 14124111301429. The next prime is 14124111301463. The reversal of 14124111301433 is 33410311142141.
It is not a de Polignac number, because 14124111301433 - 22 = 14124111301429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14124111301396 and 14124111301405.
It is not an unprimeable number, because it can be changed into a prime (14124111301463) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19245785 + ... + 19966182.
It is an arithmetic number, because the mean of its divisors is an integer number (1369360346496).
Almost surely, 214124111301433 is an apocalyptic number.
It is an amenable number.
14124111301433 is a deficient number, since it is larger than the sum of its proper divisors (2308212856519).
14124111301433 is an equidigital number, since it uses as much as digits as its factorization.
14124111301433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39219332 (or 39219325 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 14124111301433 its reverse (33410311142141), we get a palindrome (47534422443574).
The spelling of 14124111301433 in words is "fourteen trillion, one hundred twenty-four billion, one hundred eleven million, three hundred one thousand, four hundred thirty-three".
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