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1412421121403 = 5531255364513
BaseRepresentation
bin10100100011011010110…
…110111111010101111011
312000000201001112010210022
4110203122312333111323
5141120114301341103
63000505102241055
7204021053304665
oct24433266772573
95000631463708
101412421121403
114a50059a0686
121a98a0b8618b
13a3263096956
144c50c129535
1526b18867138
hex148dadbf57b

1412421121403 has 4 divisors (see below), whose sum is σ = 1412676491448. Its totient is φ = 1412165751360.

The previous prime is 1412421121399. The next prime is 1412421121469. The reversal of 1412421121403 is 3041211242141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1412421121403 - 22 = 1412421121399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1412421121703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127676726 + ... + 127687787.

It is an arithmetic number, because the mean of its divisors is an integer number (353169122862).

Almost surely, 21412421121403 is an apocalyptic number.

1412421121403 is a deficient number, since it is larger than the sum of its proper divisors (255370045).

1412421121403 is an equidigital number, since it uses as much as digits as its factorization.

1412421121403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 255370044.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 1412421121403 its reverse (3041211242141), we get a palindrome (4453632363544).

The spelling of 1412421121403 in words is "one trillion, four hundred twelve billion, four hundred twenty-one million, one hundred twenty-one thousand, four hundred three".

Divisors: 1 5531 255364513 1412421121403