14125001154513 has 4 divisors (see below), whose sum is σ = 18833334872688. Its totient is φ = 9416667436340.

The previous prime is 14125001154503. The next prime is 14125001154527. The reversal of 14125001154513 is 31545110052141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14125001154513 - 2⁹ = 14125001154001 is a prime.

It is a super-2 number, since 2×14125001154513² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14125001154503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2354166859083 + ... + 2354166859088.

It is an arithmetic number, because the mean of its divisors is an integer number (4708333718172).

Almost surely, 2^{14125001154513} is an apocalyptic number.

It is an amenable number.

14125001154513 is a deficient number, since it is larger than the sum of its proper divisors (4708333718175).

14125001154513 is an equidigital number, since it uses as much as digits as its factorization.

14125001154513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4708333718174.

The product of its (nonzero) digits is 12000, while the sum is 33.

The spelling of 14125001154513 in words is "fourteen trillion, one hundred twenty-five billion, one million, one hundred fifty-four thousand, five hundred thirteen".