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14125433 = 72017919
BaseRepresentation
bin110101111000…
…100101111001
3222120122110012
4311320211321
512104003213
61222431305
7231031010
oct65704571
928518405
1014125433
117a78713
124892535
132c0755a
141c39a77
1513904a8
hexd78979

14125433 has 4 divisors (see below), whose sum is σ = 16143360. Its totient is φ = 12107508.

The previous prime is 14125399. The next prime is 14125439. The reversal of 14125433 is 33452141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14125433 - 26 = 14125369 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14125399 and 14125408.

It is not an unprimeable number, because it can be changed into a prime (14125439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1008953 + ... + 1008966.

It is an arithmetic number, because the mean of its divisors is an integer number (4035840).

Almost surely, 214125433 is an apocalyptic number.

It is an amenable number.

14125433 is a deficient number, since it is larger than the sum of its proper divisors (2017927).

14125433 is an equidigital number, since it uses as much as digits as its factorization.

14125433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2017926.

The product of its digits is 1440, while the sum is 23.

The square root of 14125433 is about 3758.3816996149. The cubic root of 14125433 is about 241.7318763913.

Adding to 14125433 its reverse (33452141), we get a palindrome (47577574).

The spelling of 14125433 in words is "fourteen million, one hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 7 2017919 14125433