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1412550305513 = 13339105896267
BaseRepresentation
bin10100100011100010100…
…011110010011011101001
312000001001001121101001222
4110203202203302123221
5141120400334234023
63000525555151425
7204024212330024
oct24434243623351
95001031541058
101412550305513
114a5071905606
121a99182a5575
13a3283a87c59
144c5213561bb
1526b24d83cc8
hex148e28f26e9

1412550305513 has 4 divisors (see below), whose sum is σ = 1412656215120. Its totient is φ = 1412444395908.

The previous prime is 1412550305503. The next prime is 1412550305539. The reversal of 1412550305513 is 3155030552141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1412550305513 - 218 = 1412550043369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1412550305503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52934795 + ... + 52961472.

It is an arithmetic number, because the mean of its divisors is an integer number (353164053780).

Almost surely, 21412550305513 is an apocalyptic number.

It is an amenable number.

1412550305513 is a deficient number, since it is larger than the sum of its proper divisors (105909607).

1412550305513 is a wasteful number, since it uses less digits than its factorization.

1412550305513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105909606.

The product of its (nonzero) digits is 45000, while the sum is 35.

Adding to 1412550305513 its reverse (3155030552141), we get a palindrome (4567580857654).

The spelling of 1412550305513 in words is "one trillion, four hundred twelve billion, five hundred fifty million, three hundred five thousand, five hundred thirteen".

Divisors: 1 13339 105896267 1412550305513