Base | Representation |
---|---|
bin | 1100110110011110010111… |
… | …1000110100010110101011 |
3 | 1212000211000021222100102011 |
4 | 3031213211320310112223 |
5 | 3323001222101013030 |
6 | 50015122342420351 |
7 | 2655600451651546 |
oct | 315474570642653 |
9 | 55024007870364 |
10 | 14130004313515 |
11 | 4558557080602 |
12 | 17025a5a316b7 |
13 | 7b65b89a8c4c |
14 | 36bc7833b85d |
15 | 197849314b2a |
hex | cd9e5e345ab |
14130004313515 has 8 divisors (see below), whose sum is σ = 16956029596608. Its totient is φ = 11303987170560.
The previous prime is 14130004313419. The next prime is 14130004313527. The reversal of 14130004313515 is 51531340003141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14130004313515 - 213 = 14130004305323 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2849755 + ... + 6031675.
It is an arithmetic number, because the mean of its divisors is an integer number (2119503699576).
Almost surely, 214130004313515 is an apocalyptic number.
14130004313515 is a deficient number, since it is larger than the sum of its proper divisors (2826025283093).
14130004313515 is an equidigital number, since it uses as much as digits as its factorization.
14130004313515 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4070069.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 14130004313515 its reverse (51531340003141), we get a palindrome (65661344316656).
The spelling of 14130004313515 in words is "fourteen trillion, one hundred thirty billion, four million, three hundred thirteen thousand, five hundred fifteen".
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