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141300105 = 3522374211
BaseRepresentation
bin10000110110000…
…01000110001001
3100211212210022020
420123001012021
5242133100410
622004315053
73334013442
oct1033010611
9324783266
10141300105
117283a951
123b3a2a89
132337403b
1414aa22c9
15c611a70
hex86c1189

141300105 has 16 divisors (see below), whose sum is σ = 226234944. Its totient is φ = 75308480.

The previous prime is 141300097. The next prime is 141300167. The reversal of 141300105 is 501003141.

It is not a de Polignac number, because 141300105 - 23 = 141300097 is a prime.

It is a super-2 number, since 2×1413001052 = 39931439346022050, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31450 + ... + 35660.

It is an arithmetic number, because the mean of its divisors is an integer number (14139684).

Almost surely, 2141300105 is an apocalyptic number.

141300105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

141300105 is a deficient number, since it is larger than the sum of its proper divisors (84934839).

141300105 is a wasteful number, since it uses less digits than its factorization.

141300105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6456.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 141300105 is about 11886.9720702961. The cubic root of 141300105 is about 520.8517905921.

Adding to 141300105 its reverse (501003141), we get a palindrome (642303246).

The spelling of 141300105 in words is "one hundred forty-one million, three hundred thousand, one hundred five".

Divisors: 1 3 5 15 2237 4211 6711 11185 12633 21055 33555 63165 9420007 28260021 47100035 141300105