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1413003022401 = 3471001007467
BaseRepresentation
bin10100100011111101100…
…010110001000001000001
312000002012121110202220010
4110203331202301001001
5141122312233204101
63001042530335133
7204041350343235
oct24437542610101
95002177422803
101413003022401
114a52844074a3
121a9a23a2a4a9
13a33267c6479
144c5655205c5
1526b4e9ac2d6
hex148fd8b1041

1413003022401 has 4 divisors (see below), whose sum is σ = 1884004029872. Its totient is φ = 942002014932.

The previous prime is 1413003022393. The next prime is 1413003022441. The reversal of 1413003022401 is 1042203003141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1413003022401 - 23 = 1413003022393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413003022441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235500503731 + ... + 235500503736.

It is an arithmetic number, because the mean of its divisors is an integer number (471001007468).

Almost surely, 21413003022401 is an apocalyptic number.

It is an amenable number.

1413003022401 is a deficient number, since it is larger than the sum of its proper divisors (471001007471).

1413003022401 is an equidigital number, since it uses as much as digits as its factorization.

1413003022401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471001007470.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1413003022401 its reverse (1042203003141), we get a palindrome (2455206025542).

The spelling of 1413003022401 in words is "one trillion, four hundred thirteen billion, three million, twenty-two thousand, four hundred one".

Divisors: 1 3 471001007467 1413003022401