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14130065353 = 432003164057
BaseRepresentation
bin11010010100011011…
…11010111111001001
31100110202012200200211
431022031322333021
5212414244042403
610254040201121
71010104400545
oct151215727711
940422180624
1014130065353
115aa1065268
1228a41691a1
13144254b321
14980892a25
1557a77606d
hex34a37afc9

14130065353 has 8 divisors (see below), whose sum is σ = 14465978208. Its totient is φ = 13794484704.

The previous prime is 14130065351. The next prime is 14130065363. The reversal of 14130065353 is 35356003141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14130065353 - 21 = 14130065351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14130065351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4101 + ... + 168157.

It is an arithmetic number, because the mean of its divisors is an integer number (1808247276).

Almost surely, 214130065353 is an apocalyptic number.

It is an amenable number.

14130065353 is a deficient number, since it is larger than the sum of its proper divisors (335912855).

14130065353 is a wasteful number, since it uses less digits than its factorization.

14130065353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166103.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 14130065353 its reverse (35356003141), we get a palindrome (49486068494).

The spelling of 14130065353 in words is "fourteen billion, one hundred thirty million, sixty-five thousand, three hundred fifty-three".

Divisors: 1 43 2003 86129 164057 7054451 328606171 14130065353