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141301115 = 5137206279
BaseRepresentation
bin10000110110000…
…01010101111011
3100211212211200122
420123001111323
5242133113430
622004323455
73334016414
oct1033012573
9324784618
10141301115
117284068a
123b3a358b
1323374637
1414aa280b
15c611ee5
hex86c157b

141301115 has 8 divisors (see below), whose sum is σ = 170799840. Its totient is φ = 112215232.

The previous prime is 141301073. The next prime is 141301133. The reversal of 141301115 is 511103141.

141301115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141301115 - 218 = 141038971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141301093 and 141301102.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102455 + ... + 103824.

It is an arithmetic number, because the mean of its divisors is an integer number (21349980).

Almost surely, 2141301115 is an apocalyptic number.

141301115 is a deficient number, since it is larger than the sum of its proper divisors (29498725).

141301115 is a wasteful number, since it uses less digits than its factorization.

141301115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 206421.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 141301115 is about 11887.0145537052. The cubic root of 141301115 is about 520.8530315892.

Adding to 141301115 its reverse (511103141), we get a palindrome (652404256).

The spelling of 141301115 in words is "one hundred forty-one million, three hundred one thousand, one hundred fifteen".

Divisors: 1 5 137 685 206279 1031395 28260223 141301115