Base | Representation |
---|---|
bin | 10100100011111110000… |
… | …101111110011001011011 |
3 | 12000002020020211200212102 |
4 | 110203332011332121123 |
5 | 141122322114033001 |
6 | 3001043500234015 |
7 | 204041521654355 |
oct | 24437605763133 |
9 | 5002206750772 |
10 | 1413012252251 |
11 | 4a5289640a76 |
12 | 1a9a26b3b90b |
13 | a33286a8612 |
14 | 4c5668440d5 |
15 | 26b506d1e6b |
hex | 148fe17e65b |
1413012252251 has 4 divisors (see below), whose sum is σ = 1415890078104. Its totient is φ = 1410134426400.
The previous prime is 1413012252203. The next prime is 1413012252259. The reversal of 1413012252251 is 1522522103141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1413012252251 - 234 = 1395832383067 is a prime.
It is a super-2 number, since 2×14130122522512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1413012252259) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438912190 + ... + 1438913171.
It is an arithmetic number, because the mean of its divisors is an integer number (353972519526).
Almost surely, 21413012252251 is an apocalyptic number.
1413012252251 is a deficient number, since it is larger than the sum of its proper divisors (2877825853).
1413012252251 is an equidigital number, since it uses as much as digits as its factorization.
1413012252251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2877825852.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 1413012252251 its reverse (1522522103141), we get a palindrome (2935534355392).
The spelling of 1413012252251 in words is "one trillion, four hundred thirteen billion, twelve million, two hundred fifty-two thousand, two hundred fifty-one".
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