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1413012252251 = 4912877825361
BaseRepresentation
bin10100100011111110000…
…101111110011001011011
312000002020020211200212102
4110203332011332121123
5141122322114033001
63001043500234015
7204041521654355
oct24437605763133
95002206750772
101413012252251
114a5289640a76
121a9a26b3b90b
13a33286a8612
144c5668440d5
1526b506d1e6b
hex148fe17e65b

1413012252251 has 4 divisors (see below), whose sum is σ = 1415890078104. Its totient is φ = 1410134426400.

The previous prime is 1413012252203. The next prime is 1413012252259. The reversal of 1413012252251 is 1522522103141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413012252251 - 234 = 1395832383067 is a prime.

It is a super-2 number, since 2×14130122522512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413012252259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438912190 + ... + 1438913171.

It is an arithmetic number, because the mean of its divisors is an integer number (353972519526).

Almost surely, 21413012252251 is an apocalyptic number.

1413012252251 is a deficient number, since it is larger than the sum of its proper divisors (2877825853).

1413012252251 is an equidigital number, since it uses as much as digits as its factorization.

1413012252251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2877825852.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 1413012252251 its reverse (1522522103141), we get a palindrome (2935534355392).

The spelling of 1413012252251 in words is "one trillion, four hundred thirteen billion, twelve million, two hundred fifty-two thousand, two hundred fifty-one".

Divisors: 1 491 2877825361 1413012252251