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14130420353 = 72018631479
BaseRepresentation
bin11010010100011110…
…10001101010000001
31100110202212201122222
431022033101222001
5212414341422403
610254051540425
71010110406540
oct151217215201
940422781588
1014130420353
115aa1287a55
1228a42ba715
131442643a9a
14980946157
1557a7e6338
hex34a3d1a81

14130420353 has 4 divisors (see below), whose sum is σ = 16149051840. Its totient is φ = 12111788868.

The previous prime is 14130420329. The next prime is 14130420397. The reversal of 14130420353 is 35302403141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35302403141 = 46176577881.

It is a cyclic number.

It is not a de Polignac number, because 14130420353 - 220 = 14129371777 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14130420313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1009315733 + ... + 1009315746.

It is an arithmetic number, because the mean of its divisors is an integer number (4037262960).

Almost surely, 214130420353 is an apocalyptic number.

It is an amenable number.

14130420353 is a deficient number, since it is larger than the sum of its proper divisors (2018631487).

14130420353 is an equidigital number, since it uses as much as digits as its factorization.

14130420353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2018631486.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 14130420353 its reverse (35302403141), we get a palindrome (49432823494).

The spelling of 14130420353 in words is "fourteen billion, one hundred thirty million, four hundred twenty thousand, three hundred fifty-three".

Divisors: 1 7 2018631479 14130420353