1413102113 has 4 divisors (see below), whose sum is σ = 1451294100. Its totient is φ = 1374910128.

The previous prime is 1413102091. The next prime is 1413102127. The reversal of 1413102113 is 3112013141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 816130624 + 596971489 = 28568^2 + 24433^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413102113 - 2⁸ = 1413101857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1413102091 and 1413102100.

It is not an unprimeable number, because it can be changed into a prime (1413102193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19095938 + ... + 19096011.

It is an arithmetic number, because the mean of its divisors is an integer number (362823525).

Almost surely, 2^1413102113 is an apocalyptic number.

It is an amenable number.

1413102113 is a deficient number, since it is larger than the sum of its proper divisors (38191987).

1413102113 is an equidigital number, since it uses as much as digits as its factorization.

1413102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38191986.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1413102113 is about 37591.2504846540. The cubic root of 1413102113 is about 1122.1679185917.

Adding to 1413102113 its reverse (3112013141), we get a palindrome (4525115254).

The spelling of 1413102113 in words is "one billion, four hundred thirteen million, one hundred two thousand, one hundred thirteen".