Base | Representation |
---|---|
bin | 1000001110011010111… |
… | …1101011110000001011 |
3 | 111111202011002121021110 |
4 | 2003212233223300023 |
5 | 4303400403310011 |
6 | 144530024141403 |
7 | 13131540664443 |
oct | 2034657536013 |
9 | 444664077243 |
10 | 141310213131 |
11 | 54a24a2770a |
12 | 23478607863 |
13 | 10430164839 |
14 | 6ba764b123 |
15 | 3a20c7cba6 |
hex | 20e6bebc0b |
141310213131 has 16 divisors (see below), whose sum is σ = 192106552608. Its totient is φ = 92370086400.
The previous prime is 141310213129. The next prime is 141310213157. The reversal of 141310213131 is 131312013141.
It is not a de Polignac number, because 141310213131 - 21 = 141310213129 is a prime.
It is a super-3 number, since 3×1413102131313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 141310213098 and 141310213107.
It is not an unprimeable number, because it can be changed into a prime (141310213531) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1159950 + ... + 1275971.
It is an arithmetic number, because the mean of its divisors is an integer number (12006659538).
Almost surely, 2141310213131 is an apocalyptic number.
141310213131 is a deficient number, since it is larger than the sum of its proper divisors (50796339477).
141310213131 is a wasteful number, since it uses less digits than its factorization.
141310213131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2436302.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 141310213131 its reverse (131312013141), we get a palindrome (272622226272).
The spelling of 141310213131 in words is "one hundred forty-one billion, three hundred ten million, two hundred thirteen thousand, one hundred thirty-one".
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